Class 10 · Maths · Chapter 8 · NCERT Class 10 Mathematics

Introduction to Trigonometry Class 10 Notes

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Chapter mind map

The whole chapter at a glance: the big idea, then each branch and what sits under it.

Introduction to Trigonometry

The study of relationships between the sides and angles of triangles, essential for engineering, astronomy, and physical sciences.

  1. Trigonometric Ratios

    Six ratios expressing relationships between an acute angle and side lengths in a right-angled triangle.

    • Primary Ratios — sin A (opposite/hypotenuse), cos A (adjacent/hypotenuse), and tan A (opposite/adjacent).
    • Reciprocal Ratios — cosec A (1/sin), sec A (1/cos), and cot A (1/tan). cot A is also cos A/sin A.
    • Ratio Properties — Values depend only on the angle measure, not triangle size. sin A and cos A are always ≤ 1.
  2. Standard Angle Values

    Specific values for 0°, 30°, 45°, 60°, and 90° derived from geometric properties.

    • 45° Ratios — Derived from an isosceles right triangle where sides are 'a' and hypotenuse is a√2. sin 45° = cos 45° = 1/√2.
    • 30° and 60° Ratios — Derived from a bisected equilateral triangle. sin 30° = 1/2 and sin 60° = √3/2.
    • 0° and 90° Limits — As angle A approaches 0°, sin A becomes 0. As A approaches 90°, cos A becomes 0. Some ratios become undefined.
  3. Trigonometric Identities

    Equations true for all defined angles, derived from the Pythagoras Theorem.

    • Pythagorean Identities — sin² A + cos² A = 1; 1 + tan² A = sec² A; cot² A + 1 = cosec² A.
    • Domain Restrictions — Identities involving tan/sec require cos A ≠ 0 (A < 90°); cot/cosec require sin A ≠ 0 (A > 0°).
  4. Problem Solving Techniques

    Methods for calculating unknown ratios and proving complex identities.

    • Pythagoras Application — If one ratio is known (e.g., tan A = 4/3), use sides 4k and 3k to find the hypotenuse 5k.
    • Identity Proof Strategy — Convert all terms to sine and cosine to simplify expressions and match LHS to RHS.
    • Real-world Modeling — Calculating heights of towers or widths of rivers by imagining right-angled triangles.

Chapter notes

An exploration of the relationships between the sides and angles of right-angled triangles, covering trigonometric ratios, specific angle values, and fundamental identities.

The Concept of Trigonometry

Trigonometry is a branch of mathematics that studies the relationships between the sides and angles of a triangle.

The word 'trigonometry' is derived from the Greek words 'tri' (meaning three), 'gon' (meaning sides), and 'metron' (meaning measure). Historically, it was used by early astronomers to find the distances of stars and planets from the Earth. Today, it remains essential in engineering and physical sciences.

In many real-life situations, such as finding the height of a tower like the Qutub Minar or the width of a river, we can imagine right-angled triangles. By using trigonometric techniques, we can calculate these heights and distances without physical measurement.

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NCERT reference: chapter PDF pages 1, 2.

Trigonometric Ratios of an Acute Angle

Trigonometric ratios express the relationship between an acute angle of a right triangle and the lengths of its sides.

Consider a right triangle ABC, right-angled at B. For the acute angle A, the side BC is the 'side opposite to angle A', AB is the 'side adjacent to angle A', and AC is the 'hypotenuse'.

The six trigonometric ratios for angle A are defined as: sine (sin A = opposite/hypotenuse), cosine (cos A = adjacent/hypotenuse), tangent (tan A = opposite/adjacent), cosecant (cosec A = 1/sin A), secant (sec A = 1/cos A), and cotangent (cot A = 1/tan A).

It is important to note that 'sin A' is a single symbol representing the sine of angle A; it is not the product of 'sin' and 'A'. Also, the values of these ratios depend only on the measure of the angle, not on the size of the triangle.

At boundary angles, use sine/cosine ratios with their domains. For instance, cot 90° = cos 90°/sin 90° = 0, even though tan 90° is undefined. You cannot use 1/tan A where tan A itself is undefined.

ABCθAdjacent · ABBCHypotenuse · ACOpposite · BC
With θ at A, BC is opposite, AB is adjacent and AC is the hypotenuse. The right angle is at B. These names change when you choose the other acute angle. Learning sketch; use the labels and stated dimensions, not measurements from the picture.
RatioAbbreviationSide Relationship
sine of Asin ABC/AC
cosine of Acos AAB/AC
tangent of Atan ABC/AB
cosecant of Acosec AAC/BC
secant of Asec AAC/AB
cotangent of Acot AAB/BC

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If tan A = sin A / cos A, what is the ratio for cot A in terms of sin and cos?

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NCERT reference: chapter PDF pages 2, 3, 4, 5.

Calculating Ratios from a Given Value

If one trigonometric ratio is known, the others can be determined using the Pythagoras Theorem.

When we are given a ratio like tan A = 4/3, we can treat the sides as 4k and 3k, where k is a positive constant. By applying the Pythagoras Theorem (AC² = AB² + BC²), we find the third side.

Once all three sides (opposite, adjacent, and hypotenuse) are expressed in terms of k, the k values cancel out when calculating any other trigonometric ratio.

Finding Ratios from tan A

tan A = 4/3; BC = 4k, AB = 3k. AC = √((4k)² + (3k)²) = √(16k² + 9k²) = √(25k²) = 5k.

Using the sides BC=4k, AB=3k, and AC=5k, we find sin A = BC/AC = 4k/5k = 4/5 and cos A = AB/AC = 3k/5k = 3/5.

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For an acute angle A, if sin A = 3/5, what is cos A?

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NCERT reference: chapter PDF pages 5, 6.

Trigonometric Ratios of 45°

The ratios for 45° are derived from an isosceles right-angled triangle.

In a right triangle ABC where angle A = 45°, the third angle C must also be 45°. This makes the triangle isosceles, meaning AB = BC.

If we let AB = BC = a, then by Pythagoras Theorem, the hypotenuse AC = √(a² + a²) = a√2. Using these side lengths, we can define the exact values for all 45° ratios.

Values for 45°

sin 45° = a / (a√2) = 1/√2; cos 45° = a / (a√2) = 1/√2; tan 45° = a / a = 1.

Since the opposite and adjacent sides are equal, sine and cosine are identical, and tangent is exactly 1.

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What is the value of sec 45°?

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NCERT reference: chapter PDF page 10.

Trigonometric Ratios of 30° and 60°

These ratios are derived by bisecting an equilateral triangle.

Consider an equilateral triangle ABC with side length 2a. Each angle is 60°. If we draw a perpendicular AD from A to BC, it bisects angle A into two 30° angles and bisects side BC into two segments of length 'a'.

In the resulting right triangle ABD, the hypotenuse AB = 2a and the base BD = a. Using Pythagoras Theorem, the height AD = √((2a)² - a²) = √(3a²) = a√3. We use these lengths to find the ratios for both 30° and 60°.

Anglesincostan
30°1/2√3/21/√3
60°√3/21/2√3

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Why is sin 30° equal to cos 60°?

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NCERT reference: chapter PDF pages 10, 11.

The rest of this chapter

Keep reading Introduction to Trigonometry, free

  1. Locked: 1. Trigonometric Ratios of 0° and 90°
  2. Locked: 2. Summary Table of Specific Angles
  3. Locked: 3. Fundamental Trigonometric Identities
  4. Locked: 4. Proving Trigonometric Identities

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