Class 8 · Maths · Chapter 2 · NCERT Class 8 Mathematics Part 1

Power Play Class 8 Notes

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Chapter notes

CLASS 8 MATHS · PART 1 · CHAPTER 2 · STUDY NOTES

Power Play

Understand power play through short explanations, labelled models and original practice. Read one topic, explain it in your own words, then check.

01

UNDERSTAND · APPLY · CHECK

Doubling makes bigger changes each time

Adding and multiplying are different growth rules. Watch how their totals separate.

Add the same amount or multiply by the same factor?

Total (tokens)

Step (whole step)

Highlight a line or construction
  • Add 3 each step · Start at 1, then repeatedly add 3.
  • Double each step · Start at 1, then repeatedly multiply by 2.

The same linear axes compare two fictional token rules. At step 0 both totals are 1. Straight segments join whole-step observations.

Read the plotted values
Add 3 each step
StepTotal
01
14
27
310
413
516
619
Double each step
StepTotal
01
12
24
38
416
532
664
Linear growth
Adding the same amount at every equal step.
Exponential growth
Multiplying by the same positive factor at every equal step.

A doubling rule starting with 1 gives 1, 2, 4, 8, 16, 32 and 64. The differences get larger, even though the multiplier stays 2.

Paper folding is a useful mathematical model of doubling thickness. Many folds are physically impossible for ordinary paper: the model is not a building plan.

WORKED IDEA

Five doublings of an initial amount v

Final amount = v × 2⁵ = 32v

Keep the starting amount. The factor 32 alone is not the final quantity unless v = 1.

Take a moment. What do you think?

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Question

A model doubles daily and fills a container on day 12. On which day is it half full?

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NCERT reference: chapter PDF pages 1, 2, 3, 17, 18.

02

UNDERSTAND · APPLY · CHECK

The base is the repeated factor; the exponent counts it

Read the small raised number as an instruction to multiply equal factors.

Count factors, not additions

Count factors, not additionsEach circle represents one equal factor, not a quantity of three separate objects.3⁴: four factors of 333333 × 3 × 3 × 3 = 81
Each circle represents one equal factor, not a quantity of three separate objects.
Base
The number or expression being repeatedly multiplied.
Exponent
For a positive integer exponent, the number of equal factors.

3⁴ = 3 × 3 × 3 × 3 = 81. It is different from 4 × 3 = 12.

Parentheses matter. (−3)² = 9, while −3² means −(3²) = −9. Even powers of a negative base are positive; odd powers are negative.

Let’s look a little closer.

Go deeper: Zero as a base

For a positive integer n, 0ⁿ = 0. This chapter does not define 0⁰ or negative powers of zero.

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Question

Write a × a × b × b × b in compact form.

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NCERT reference: chapter PDF pages 3, 4, 5.

03

UNDERSTAND · APPLY · CHECK

Join same-base factor groups by adding exponents

When the bases match, join their lists of equal factors.

Three factors join two factors

Three factors join two factorsBlue shows three factors and orange shows two. The base stays 2; only the count of factors changes.2³2²Five factors: 2⁵
Blue shows three factors and orange shows two. The base stays 2; only the count of factors changes.
Same-base product law
aᵐ × aⁿ = aᵐ⁺ⁿ. For integer exponents that may be zero or negative, require a ≠ 0.

2³ × 2² has three factors of 2 followed by two more. Together they make five: 2⁵ = 32.

This rule is about multiplication. 2³ + 2² = 8 + 4 = 12; adding the exponents would give the wrong answer.

  1. 1

    Check that both bases are 2.

  2. 2

    Count 3 + 2 equal factors.

  3. 3

    Write 2⁵ and, if needed, evaluate it as 32.

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Question

Simplify 7² × 7⁴ without calculating a large integer.

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NCERT reference: chapter PDF page 6.

04

UNDERSTAND · APPLY · CHECK

A power of a power multiplies the counts

Expand the outer power as repeated groups, then count how many factors are inside all the groups.

Three groups, two factors in each

Three groups, two factors in eachEach outlined group is one 2². Three groups contain six factors of 2.(2²)³2 × 22 × 22 × 2
Each outlined group is one 2². Three groups contain six factors of 2.
Power-of-a-power law
(aᵐ)ⁿ = aᵐⁿ; for arbitrary integer exponents here, use a ≠ 0.
Power of a product
(ab)ⁿ = aⁿbⁿ, where the expressions are defined.

(2²)³ is three groups of two factors. It equals 2⁶ = 64.

A shared exponent lets you combine different bases: 2⁴ × 3⁴ = (2 × 3)⁴ = 6⁴. A power of a sum does not work this way.

WORKED IDEA

A quotient with a shared exponent

12³ ÷ 4³ = (12/4)³ = 3³ = 27

The denominator must be nonzero. This follows by dividing matching factors.

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Question

Is (2 + 3)² equal to 2² + 3²?

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NCERT reference: chapter PDF pages 6, 7.

05

UNDERSTAND · APPLY · CHECK

Multiply choices when every pairing is allowed

Draw a small branching tree before working with a long code.

Trace one branch for each permitted badge

Trace one branch for each permitted badgeEach final dot is a different badge. The diagram assumes every colour-symbol pairing is permitted.Start2 colours3 symbols each6 complete paths
Each final dot is a different badge. The diagram assumes every colour-symbol pairing is permitted.
Multiplication principle
If each of m choices can be followed by each of n choices, there are mn ordered combinations.

Suppose a badge has two colour choices and three symbol choices. Each colour can pair with every symbol, so there are 2 × 3 = 6 badges.

A four-slot code with digits 0–9 has 10⁴ possibilities only if repetitions and a leading zero are allowed. A four-digit number has different rules.

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Question

How many three-slot codes use only A or B, allowing repetition?

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NCERT reference: chapter PDF pages 8, 9.

06

UNDERSTAND · APPLY · CHECK

Divide matching factors; zero power becomes 1

Cancellation explains subtraction of exponents.

Cancel matching factors

Cancel matching factorsThe first two numerator factors match the two denominator factors. Cancellation leaves 5 × 5, not zero.5⁴5²Two factors remain: 5²
The first two numerator factors match the two denominator factors. Cancellation leaves 5 × 5, not zero.
Quotient law
aᵐ ÷ aⁿ = aᵐ⁻ⁿ, for a ≠ 0 and integer m, n.
Zero exponent
a⁰ = 1 for a ≠ 0.

5⁴ ÷ 5² cancels two factors in the numerator and denominator. Two remain, giving 5².

Dividing any nonzero power by itself gives 1. The quotient law then gives aⁿ ÷ aⁿ = a⁰ = 1. Zero is excluded because division by zero is undefined.

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Question

What is 13⁶ ÷ 13⁶? Explain using both cancellation and exponents.

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NCERT reference: chapter PDF pages 9, 10.

07

UNDERSTAND · APPLY · CHECK

A negative exponent means a reciprocal

Keep dividing by the base as you move down one exponent at a time.

Divide by 3 at every arrow

Divide by 3 at every arrowThe successive exponent labels are 2, 1, 0, −1 and −2. This is a sequence of divisions, not equally spaced values on a number line.9311/31/9
The successive exponent labels are 2, 1, 0, −1 and −2. This is a sequence of divisions, not equally spaced values on a number line.
Negative exponent
a⁻ⁿ = 1/aⁿ, for nonzero a and positive integer n.
Reciprocal
The number that multiplies a nonzero number to give 1.

The sequence 3², 3¹, 3⁰, 3⁻¹, 3⁻² has values 9, 3, 1, 1/3 and 1/9. Each step divides by 3.

A negative exponent does not make the value negative. For example, 4⁻² = 1/16 is positive. A negative base and a negative exponent are different ideas.

WORKED IDEA

Combine integer exponents

6⁻² × 6⁵ = 6³

The same-base product law still applies: −2 + 5 = 3. The base is nonzero.

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Question

Calculate (−2)⁻³.

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NCERT reference: chapter PDF pages 10, 11, 12.

08

UNDERSTAND · APPLY · CHECK

Powers of ten explain both sides of the decimal point

Each step right in a decimal place-value chart divides the place value by 10.

Follow the descending place values

Follow the descending place valuesThe five columns represent the digits of 708.04. A decimal point separates the ones and tenths columns; it is not a digit.1001010.10.0170804
The five columns represent the digits of 708.04. A decimal point separates the ones and tenths columns; it is not a digit.
Place value
The value contributed by a digit because of its position.

708.04 = 7 × 10² + 0 × 10¹ + 8 × 10⁰ + 0 × 10⁻¹ + 4 × 10⁻². Zero holds empty places.

Multiplying a number by 10 moves each digit to a place worth ten times as much. Describe the value change, rather than treating the decimal point as an object that moves.

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Question

What does the digit 6 contribute in 25.063?

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NCERT reference: chapter PDF page 12.

09

UNDERSTAND · APPLY · CHECK

Write a large or small number as a coefficient times 10

For a positive quantity, put one nonzero digit before the decimal point and record the scale with a power of 10.

Keep the value unchanged

Keep the value unchangedAt each step the coefficient is divided by 10 and the power-of-ten factor is multiplied by 10. The final coefficient is between 1 and 10.4720047.2 × 10³4.72 × 10⁴÷ 1000; × 10³÷ 10; × 10
The first move rewrites 47200 as 47.2 × 10³. The next divides the coefficient by 10 and multiplies the power-of-ten factor by 10. All three expressions are equal; only the last has its coefficient between 1 and 10.
Scientific notation
For a positive number, c × 10ᵏ with 1 ≤ c < 10 and integer k.
Coefficient
The factor c that states the leading size within a power-of-ten scale.

47,200 = 4.72 × 10⁴. Since 10⁴ = 10,000, multiply to check the original number.

0.00062 = 6.2 × 10⁻⁴. The negative exponent records a small positive quantity. A lakh is 10⁵, a crore is 10⁷, a million is 10⁶ and a billion is 10⁹.

Go deeper: Zero and negative numbers

Zero cannot have a nonzero coefficient between 1 and 10. For a negative nonzero number, keep the minus sign and apply the same coefficient rule to its absolute value. A googol is 10¹⁰⁰; a googolplex is 10 raised to a googol, not 10 × a googol.

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Question

Convert 3.06 × 10⁵ into an ordinary number.

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NCERT reference: chapter PDF pages 13, 14, 18, 25.

10

UNDERSTAND · APPLY · CHECK

Compare scales and convert units before dividing

An exponent helps you see scale. For calculations, keep the units and coefficient as well.

Use thousands as the common unit

Value (number)

  • Number-line marks · Only horizontal position represents the number.
  1. 18 · (8, 0)
  2. 212 · (12, 0)

The two values are 8 thousand and 12 thousand. The coordinate scale is thousands of items, not individual items.

Read the plotted values
Number-line marks
ValueHeight
80
120
Ratio of quantities
One quantity divided by another expressed in the same units.
Approximation
A nearby value used with an explicit level of precision.

A fictional store has 6 × 10⁶ pencils and another has 3 × 10⁴. The first has (6/3) × 10² = 200 times as many.

Compare equal powers of ten by their coefficients. If exponents differ, first rewrite at the same scale. Rounded inputs lead to an approximate result, not an exact count.

WORKED IDEA

Same units first

(2.4 × 10⁴ m) ÷ (6 × 10² m) = 40

Read the quotient as (2.4 × 10⁴)/(6 × 10²). Metres cancel, leaving a dimensionless ratio.

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Question

Which is greater, 8 × 10³ or 1.2 × 10⁴?

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NCERT reference: chapter PDF pages 19, 20, 21, 23, 24, 25.

11

UNDERSTAND · APPLY · CHECK

Convert seconds step by step, with stated assumptions

A power of ten may be a short expression but represent a very long time.

Convert with the correct factors

Convert with the correct factorsThe two divisions are by 60. Converting hours to days needs a further division by 24, not 60.seconds÷ 60minutes÷ 60hours
The two divisions are by 60. Converting hours to days needs a further division by 24, not 60.
Conversion factor
A ratio of equal amounts in different units, such as 60 seconds per minute.

There are 60 seconds in a minute, 3,600 in an hour and 86,400 in a day. Divide by the relevant conversion factor.

10⁶ seconds is about 11.57 days, whereas 10⁹ seconds is about 31.7 years using 365 days per year. A factor of 1,000 makes an enormous difference.

  1. 1

    Choose the requested unit: days.

  2. 2

    Use 1 day = 24 × 60 × 60 = 86,400 seconds.

  3. 3

    Calculate 172,800/86,400 = 2.

Go deeper: Check claims with a model

For estimates, say what you assume. A fictional 180 km journey at 30 km per day takes 6 days under that daily-distance assumption. Rest days and changing speed would alter the answer. An estimate is useful without pretending to know exact real-world data.

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Question

How many days are 1.728 × 10⁵ seconds?

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NCERT reference: chapter PDF pages 21, 22, 23, 24.

CHAPTER RECAP

Doubling makes bigger changes each time → The base is the repeated factor; the exponent counts it → Join same-base factor groups by adding exponents → A power of a power multiplies the counts → Multiply choices when every pairing is allowed → Divide matching factors; zero power becomes 1 → A negative exponent means a reciprocal → Powers of ten explain both sides of the decimal point → Write a large or small number as a coefficient times 10 → Compare scales and convert units before dividing → Convert seconds step by step, with stated assumptions

Learnijoy explanations and visuals based on NCERT Class VIII Mathematics · Chapter 2 ↗. Exploring visuals and revealing answers do not record completion.

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