CLASS 8 MATHS · PART 2 · CHAPTER 1 · STUDY NOTES
Fractions in Disguise
Understand fractions in disguise through short explanations, labelled models and original practice. Read one topic, explain it in your own words, then check.
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Percent means out of one hundred
A percentage is a fraction with denominator 100.Three quarters = 75%
- Orange length
- The selected amount.
- Full length
- The reference whole.
- Percentage
- A way to express a fraction per hundred: p% = p/100.
3/4 = 75/100 = 75%. The whole is the same; only the way we describe its share changes.
Multiply a fraction by 100 to write its percentage. For example 2/5 × 100 = 40, so 2/5 = 40%.
Convert back
32% = 32/100 = 8/25Write the percentage over 100 and simplify.
Take a moment. What do you think?
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Question
Write 7/20 as a percentage.
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Always identify the whole first
A larger percentage does not always mean a larger amount when the wholes differ.Compare amounts using one common scale
- Percentage amount
- p% of W is (p/100) × W.
25% of 120 g is 30 g. But 40% of 60 g is only 24 g. Both the percentage and the reference whole matter.
For mental calculations, 10% is one tenth and 5% is half of that. 15% can be found as 10% + 5% of the same whole.
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Question
Find 15% of 240.
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Fraction, decimal and percent name the same value
Move between the three forms without changing the amount.Three names, one value
- Decimal equivalent
- A base-ten representation of the same number as a fraction.
| Fraction | Decimal | Percent |
|---|---|---|
| 1/2 | 0.5 | 50% |
| 1/4 | 0.25 | 25% |
| 1/5 | 0.2 | 20% |
| 1/20 | 0.05 | 5% |
0.35 = 35/100 = 35%. To turn a decimal into a percentage, multiply its value by 100 and add the percent sign.
For a ratio 2:3, the first ingredient is 2 of 5 total parts. Its share is 2/5 = 0.4 = 40%, not 2/3.
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Question
A student earns 27 of 36 marks. Give the fraction, decimal and percentage.
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If you know a part, reverse the multiplication
Write an equation for the given percentage, then solve for the whole.45 km is 30% of 150 km
- Orange length
- The selected amount.
- Full length
- The reference whole.
- Reference whole
- The amount treated as 100% in a percentage comparison.
If 30% of a journey is 45 km, then 0.30W = 45. Dividing gives W = 150 km.
The remaining 70% is 150 − 45 = 105 km. It is 70% of the whole, not 70% of the 45 km part.
- 1
Name the whole W.
- 2
Write (percentage/100) × W = known part.
- 3
Divide by the percentage expressed as a decimal.
- 4
Multiply back to check.
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Question
40% of a number is 28. Find the number.
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More than 100% means more than the reference whole
100% is one copy of the reference amount; 150% is one and a half copies.Copies of the reference amount
Value (number)
- Number-line marks · Only horizontal position represents the number.
- 10 · (0, 0)
- 21 · (1, 0)
- 31.5 · (1.5, 0)
- 42 · (2, 0)
0, 1, 1.5 and 2 copies correspond to 0%, 100%, 150% and 200%.
Read the plotted values
| Value | Height |
|---|---|
| 0 | 0 |
| 1 | 0 |
| 1.5 | 0 |
| 2 | 0 |
- Percentage of a target
- Actual amount ÷ target × 100%.
A target of 200 items and an output of 300 gives 300/200 × 100 = 150% of the target.
Being 150% of the original is the same as increasing by 50%. These two percentage statements have different wording but the same new amount.
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Question
A quantity doubles. What percent of its old value is it, and what is the percentage increase?
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Measure the change against the original amount
Percentage change uses the starting amount as its base.Same change, different bases
- Percentage increase
- (New − original)/original × 100%, for a positive original value.
- Percentage decrease
- (Original − new)/original × 100%, for a positive original value.
A price rising from ₹80 to ₹100 increases by ₹20, which is 20/80 × 100 = 25%.
Returning from ₹100 to ₹80 is a decrease of 20/100 × 100 = 20%. The change is ₹20 both times, but the bases differ.
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Question
A count falls from 160 to 120. Find the percentage decrease.
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Cost, marked price and selling price have different roles
Choose the correct base before calculating any percentage.Track the transaction
- Cost price (CP)
- The amount paid to obtain the item in the stated transaction.
- Selling price (SP)
- The amount received when it is sold.
- Marked price (MP)
- The displayed price before a stated discount.
For CP ₹400 and SP ₹460, profit is ₹60. Profit as a percentage of cost is 60/400 × 100 = 15%.
A 20% discount on MP ₹600 gives SP = 0.8 × 600 = ₹480. Discount uses marked price; this chapter’s profit-on-cost calculation uses cost price.
Let’s look a little closer.
Go deeper: Profit and margin need a named base
Profit divided by selling revenue is a different percentage from profit divided by cost. Gross profit deducts the cost of goods; net profit also deducts the relevant other expenses. Always state which measure and denominator you mean.
A classroom tax example may add a stated hypothetical rate to a tax-exclusive price. It is not a statement of current GST law or rates.
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Question
An item costs ₹250 and sells for ₹225. Find the loss percentage on cost.
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Compounding changes the base after each period
When a gain is added back, the next percentage is calculated on a larger amount.Fixed-base and changing-base growth
Principal plus gains (rupees)
Time (years)
- No compounding · Gain ₹100 each year.
- Annual compounding · Multiply the previous amount by 1.1.
Hypothetical mathematics model: constant rate, no fees or tax. Points show year ends; connecting lines guide comparison.
Read the plotted values
| Time | Principal plus gains |
|---|---|
| 0 | 1000 |
| 1 | 1100 |
| 2 | 1200 |
| 3 | 1300 |
| Time | Principal plus gains |
|---|---|
| 0 | 1000 |
| 1 | 1100 |
| 2 | 1210 |
| 3 | 1331 |
- Principal
- The starting amount in the model.
- Compounding
- Adding each period’s gain to the amount used for the next period.
Start with ₹1000 at a hypothetical 10% each year. With annual compounding: ₹1100 after year 1, ₹1210 after year 2 and ₹1331 after year 3.
Without compounding, interest is ₹100 each year on the original ₹1000, giving total principal plus interest ₹1300 after three years.
Use a decimal rate
A = P(1 + r)^tFor 10%, use r = 0.10, not 10. Here t counts equal compounding periods.
No compounding
A = P(1 + rt)Interest is Prt; the total also includes P. Rates and time units must match.
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Question
Find the amount from ₹2000 after two years at a hypothetical 5%, compounded annually.
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Successive percentages multiply
A decrease leaves a multiplier below 1. Apply each multiplier to the new amount.Apply one multiplier at a time
- Depreciation
- A reduction in value in the stated model; actual resale values need not follow a fixed percentage.
A ₹5000 model value falling 10% twice becomes 5000 × 0.9 × 0.9 = ₹4050. The total fall is 19%, not 20%.
A 20% increase followed by a 20% decrease gives 1.2 × 0.8 = 0.96 of the start: a 4% fall. The second percentage uses a different base.
Go deeper: A percentage of a subgroup
If 40% of a group are in Grade 8 and 50% of those Grade 8 students choose art, the art subgroup is 0.4 × 0.5 = 0.2, or 20% of the whole group. Do not add the two percentages.
Keep full precision while calculating; round a final estimate when appropriate. People and discrete objects require a sensible whole-number interpretation.
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Question
Two successive discounts are 20% and 10%. What is their combined discount?
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Percentages describe shares, not group sizes
A graph of percentages does not tell you how many people are in each group unless its counts are also known.Percentage and count answer different questions
- Comparable base
- A clearly identified reference quantity used to interpret a share.
If 60% of 20 students and 40% of 50 students use the library, the counts are 12 and 20. The larger percentage has the smaller count.
For a fictional buy-two-get-one-free offer on identical items, you pay for 2 of 3: an effective discount of 1/3, or 33⅓%, if you receive and use all three.
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Question
Why can’t we compare the number of users from percentages alone?
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