Class 8 · Maths · Chapter 7 · NCERT Class 8 Mathematics Part 1

Proportional Reasoning – 1 Class 8 Notes

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Chapter notes

CLASS 8 MATHS · PART 1 · CHAPTER 7 · STUDY NOTES

Proportional Reasoning – 1

Understand proportional reasoning – 1 through short explanations, labelled models and original practice. Read one topic, explain it in your own words, then check.

01

UNDERSTAND · APPLY · CHECK

Resize both directions by the same factor

A picture keeps its shape when its width and height grow in the same ratio.

Compare outlines using equal units

y (units)

x (units)

Highlight a line or construction
  • Original 8 by 6 · Original 8 by 6
  • Correct 12 by 9 · Both dimensions multiplied by 1.5.
  • Stretched 12 by 6 · Only the width changed.
  1. 18 by 6 · (8, 6)
  2. 212 by 9 · (12, 9)
  3. 312 by 6 · (12, 6)

All outlines start at the origin so their proportions can be compared. One horizontal unit equals one vertical unit. Equal units on both axes.

Read the plotted values
Original 8 by 6
xy
00
80
86
06
00
Correct 12 by 9
xy
00
120
129
09
00
Stretched 12 by 6
xy
00
120
126
06
00
Scale factor
The multiplier applied to each corresponding length.
Aspect ratio
The ratio of width to height.

An 8 cm by 6 cm picture has ratio 4:3. Multiplying both lengths by 1.5 gives 12 cm by 9 cm, still 4:3.

Changing only the width to 12 cm gives ratio 2:1 and stretches the picture. Adding the same amount to both lengths usually changes the ratio too.

Take a moment. What do you think?

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Question

A 10 by 8 picture is enlarged to width 15. What height keeps its shape?

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NCERT reference: chapter PDF pages 1, 2.

02

UNDERSTAND · APPLY · CHECK

A ratio tells us how two amounts compare

Write the amounts in the stated order and use the same units for like quantities.

Part-to-part and part-to-whole

Part-to-part and part-to-wholeFive equal counters show the difference between comparing red with blue and comparing red with the total.2 red : 3 blueRed share = 2 of 5
Five equal counters show the difference between comparing red with blue and comparing red with the total.
Ratio
a:b compares an amount a with an amount b; the order matters.
Equivalent ratios
Ratios obtained by multiplying or dividing both terms by the same nonzero number.

12 red beads to 18 blue beads is 12:18 = 2:3. Divide both terms by their HCF, 6.

2:3 means 2 red for every 3 blue. It does not mean that 2/3 of all the beads are red: the red share is 2/(2 + 3) = 2/5.

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Question

Simplify 45 minutes to 2 hours.

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NCERT reference: chapter PDF pages 3, 4.

03

UNDERSTAND · APPLY · CHECK

Keep the recipe constant by multiplying both parts

If a batch becomes three times as large, each ingredient becomes three times as large.

A constant recipe passes through zero

Concentrate (spoons)

Water (glasses)

  • Same recipe · 1.5 spoons per glass.
  1. 1Original batch · (4, 6)
  2. 2New batch · (10, 15)

Equal measures and unchanged recipe are assumed. No water means no concentrate in this model.

Read the plotted values
Same recipe
WaterConcentrate
00
46
1015
1218
Direct proportion
Two quantities are directly proportional when their ratio stays constant, so y = kx.

A recipe uses 4 glasses of water and 6 spoons of concentrate. A new batch of 10 glasses needs 6 × (10/4) = 15 spoons.

This assumes equal-sized glasses and spoons and the same recipe. A ratio alone does not guarantee the strength or quality of a real building material.

  1. 1

    Find the scale factor: new amount ÷ old amount.

  2. 2

    Multiply the matching amount by that same factor.

  3. 3

    Check that the ratio remains unchanged.

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Question

A recipe uses 3 cups of rice for 5 people. How much for 20 people at the same serving size?

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NCERT reference: chapter PDF pages 4, 5, 6, 7.

04

UNDERSTAND · APPLY · CHECK

Equal additions do not usually keep a ratio

Ask whether one amount is always a fixed multiple of the other.

A fixed fee changes the relationship

Total bill (rupees)

Items (count)

Highlight a line or construction
  • With ₹20 fee · Cost = 3n + 20.
  • No fixed fee · Cost = 3n.
  1. 1Fixed fee · (0, 20)
  2. 2No fee · (0, 0)

Whole-number item counts are intended. Lines help compare the rules between those counts.

Read the plotted values
With ₹20 fee
ItemsTotal bill
020
535
1050
No fixed fee
ItemsTotal bill
00
515
1030
Constant difference
A fixed amount obtained by subtracting two quantities; this differs from a constant ratio.

A child aged 4 and an adult aged 28 have ratio 1:7. Four years later their ages are 8 and 32, ratio 1:4. Their age difference stays 24.

A price of ₹3 per item plus ₹20 delivery gives cost 3n + 20. Doubling the item count does not double the total bill.

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Question

Is a bill of ₹5 per item with no fixed fee directly proportional to item count?

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NCERT reference: chapter PDF pages 6, 12, 13.

05

UNDERSTAND · APPLY · CHECK

Three known values give the fourth

Write the matching quantities in corresponding positions before calculating.

Use a unit rate or a scale factor

Use a unit rate or a scale factorThe same unit price is assumed; discounts or fixed charges would change the model.5 books →₹801 book → ₹168 books →₹128
The same unit price is assumed; discounts or fixed charges would change the model.
Proportion
An equality of ratios, a:b = c:d, where the required denominators are nonzero.
Rule of three
A way of finding a fourth proportional value from three known values.

If a/b = c/d, cross multiplication gives ad = bc. To find d when a ≠ 0, use d = bc/a.

At a constant speed, 60 km in 90 minutes gives 120 km in 180 minutes. Converting 3 hours to 180 minutes comes before scaling.

WORKED IDEA

Check the ratios

5/80 = 8/128 = 1/16

Keep books above books and cost above cost in the proportion.

Let’s look a little closer.

Go deeper: Trairāśika

The rule of three is also discussed in Indian mathematical traditions using the term Trairāśika. Its mathematics here is the equality of two ratios, not a rule to apply when a ratio changes.

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Question

Five identical notebooks cost ₹80. What do eight cost at the same unit price?

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NCERT reference: chapter PDF pages 9, 10, 11.

06

UNDERSTAND · APPLY · CHECK

Compare costs for the same amount

Different pack sizes become comparable after finding one unit price.

Compare equal quantities

Unit price (rupees/kg)

Pack (comparison index)

  • Unit-price points · 1 is the 250 g pack; 2 is the 1 kg pack.
  1. 1250 g: ₹600/kg · (1, 600)
  2. 21 kg: ₹480/kg · (2, 480)

The horizontal positions identify two packs; they are not a continuous quantity. The vertical values are comparable prices per kilogram.

Read the plotted values
Unit-price points
PackUnit price
1600
2480
Unit rate
An amount per one unit of another quantity, such as rupees per kilogram.

A 250 g pack costing ₹150 has unit price ₹150/0.25 kg = ₹600/kg. A 1 kg pack at ₹480 is cheaper per kilogram.

Pack prices need not be directly proportional to size because packaging, discounts and other costs may differ.

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Question

Which has lower unit price: 300 g for ₹90 or 500 g for ₹160?

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NCERT reference: chapter PDF pages 11, 12.

07

UNDERSTAND · APPLY · CHECK

Find the value of one ratio part

Add the ratio parts first. Then divide the total into that many equal parts.

Five equal parts make the whole

Five equal parts make the wholeThe total ₹65 is divided into five equal ₹13 parts. The first share takes two parts, the second three.2 parts3 partsEach part = ₹13
The total ₹65 is divided into five equal ₹13 parts. The first share takes two parts, the second three.
Proportional sharing
Dividing a total so that the shares have a specified ratio.

Share ₹65 in the ratio 2:3. There are 5 parts, so one part is ₹65/5 = ₹13. The shares are ₹26 and ₹39.

Always check both the sum and the ratio. If you are sharing indivisible objects, each share must be a whole number.

  1. 1

    Add the ratio terms: 2 + 3 = 5.

  2. 2

    Divide the total by 5 to find one part.

  3. 3

    Multiply one part by each term.

  4. 4

    Check ₹26 + ₹39 = ₹65 and 26:39 = 2:3.

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Question

Share 84 stickers in the ratio 3:4.

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NCERT reference: chapter PDF pages 14, 15, 16.

08

UNDERSTAND · APPLY · CHECK

Change the ingredient that is allowed to change

Find the current amounts before trying to adjust the mixture.

Hold blue fixed; increase yellow

Hold blue fixed; increase yellowA composition schematic, not a volume-scale vessel. Blue is unchanged; the extra band identifies the added yellow.12 : 3012 : 36Add 6 yellow
A composition schematic, not a volume-scale vessel. Blue is unchanged; the extra band identifies the added yellow.
Mixture ratio
The relative amounts of the named ingredients, in the stated order.

A 42 mL model mixture has blue:yellow = 2:5, giving 12 mL blue and 30 mL yellow. To change to 1:3 by adding only yellow, blue stays 12 mL.

Yellow must become 3 × 12 = 36 mL, so add 6 mL. The new total is 48 mL; it is not still 42 mL. Assume the measured ingredient volumes add in this model.

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Question

A model mixture has 10 units of A and 20 of B. How much B should be added to make A:B = 1:4?

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NCERT reference: chapter PDF pages 16, 17.

09

UNDERSTAND · APPLY · CHECK

Area conversions square the length factor

A square metre contains a 100 by 100 grid of square centimetres.

Convert each side

Convert each sideA square schematic of one square metre. Its side lengths become 100 cm, so the area conversion factor is squared.100 cm100 cm10,000 cm²The same area is 1 m²
A square schematic of one square metre. Its side lengths become 100 cm, so the area conversion factor is squared.
Area conversion
A conversion in which the length factor is applied in both directions.
Hectare
An area of 10,000 square metres.
UnitExact equivalent
1 m²10,000 cm²
1 hectare10,000 m²
1 L1000 mL
1 mL1 cm³

1 m = 100 cm, so 1 m² = 100 × 100 = 10,000 cm². It is not 100 cm².

1 L = 1000 mL and 1 mL = 1 cm³. Rounded conversions, such as metres to feet, should be marked approximate.

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Question

Convert 2.5 m² to cm².

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NCERT reference: chapter PDF pages 17, 18.

10

UNDERSTAND · APPLY · CHECK

An offset or a whole-object constraint changes the method

Some calculations need an added amount or a final rounding decision.

Temperature conversion has an offset

Temperature (°F)

Temperature (°C)

  • Fahrenheit conversion · F = 1.8C + 32.
  1. 10°C = 32°F · (0, 32)
  2. 225°C = 77°F · (25, 77)

This is a conversion graph, not direct proportion. Its vertical intercept is 32°F.

Read the plotted values
Fahrenheit conversion
TemperatureTemperature
032
2577
100212
Offset
A fixed addition in a conversion rule, such as the +32 in °F = 9°C/5 + 32.

The Celsius–Fahrenheit rule is F = 9C/5 + 32. Because of +32, it is not direct proportion. At 25°C, F = 45 + 32 = 77°F.

If a bus seats 40 and 95 people must travel at once, 95/40 = 2.375 tells us that 2 buses are insufficient. We need 3 whole buses.

Go deeper: Fixed journey: faster means less time

For a fixed distance, speed × time stays constant. Doubling speed halves travel time if speed is constant during each journey. This is inverse proportion, studied further in Part 2.

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Question

How many 12-capacity boxes are needed for 50 objects if no box may exceed capacity?

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NCERT reference: chapter PDF pages 18, 19.

CHAPTER RECAP

Resize both directions by the same factor → A ratio tells us how two amounts compare → Keep the recipe constant by multiplying both parts → Equal additions do not usually keep a ratio → Three known values give the fourth → Compare costs for the same amount → Find the value of one ratio part → Change the ingredient that is allowed to change → Area conversions square the length factor → An offset or a whole-object constraint changes the method

Learnijoy explanations and visuals based on NCERT Class VIII Mathematics · Chapter 7 ↗. Exploring visuals and revealing answers do not record completion.

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